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OK. This is the stuff I really like to mess with, so I'll stick my neck out here.
Acetone, (CH3)2CO in general use thermodynamics, will absorb oxygen into
a
heavier compound with carbon.
Gasoline, as we all know, has lots of carbon, and there is (hopefully) alot of
oxygen to be had. So, in chemical terms we do have an opportunity to "get" some free O into our equation.
But here's the rub! (CH3)2CO has a very low (in comparison) boiling point, about 128f degrees. C86H14 (good gas) has a boiling point up to 4! times higher. So, it would stand on reason that we could loose a lot of our (CH3)2CO just in the heat losses in the intake stream, As a result, we would have to mix a "bucket-load" of the acetone to keep our supposedly "free" oxygen in some sort of useful gain by proportion in the combustion event. And since the specific gravity of acetone is just a 'tick' heavier than gas, you are going to need a much bigger fuel tank.
BTW, the latent heat of vaporization for acetone is about half that of methanol, which in itself has about half the latency of gasoline, which means to say, that for every ounce burned it takes 4 times the amount of acetone to get the same calorie
release of the same ounce (by volume) of gasoline.
Now if I could just figure out that magnetic bubble thing..............